Optimal. Leaf size=79 \[ \frac{\sin (c+d x) \cos ^5(c+d x)}{6 a^3 d}+\frac{5 \sin (c+d x) \cos ^3(c+d x)}{24 a^3 d}+\frac{5 \sin (c+d x) \cos (c+d x)}{16 a^3 d}+\frac{5 x}{16 a^3} \]
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Rubi [A] time = 0.0479145, antiderivative size = 79, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 4, integrand size = 14, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.286, Rules used = {3657, 12, 2635, 8} \[ \frac{\sin (c+d x) \cos ^5(c+d x)}{6 a^3 d}+\frac{5 \sin (c+d x) \cos ^3(c+d x)}{24 a^3 d}+\frac{5 \sin (c+d x) \cos (c+d x)}{16 a^3 d}+\frac{5 x}{16 a^3} \]
Antiderivative was successfully verified.
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Rule 3657
Rule 12
Rule 2635
Rule 8
Rubi steps
\begin{align*} \int \frac{1}{\left (a+a \tan ^2(c+d x)\right )^3} \, dx &=\int \frac{\cos ^6(c+d x)}{a^3} \, dx\\ &=\frac{\int \cos ^6(c+d x) \, dx}{a^3}\\ &=\frac{\cos ^5(c+d x) \sin (c+d x)}{6 a^3 d}+\frac{5 \int \cos ^4(c+d x) \, dx}{6 a^3}\\ &=\frac{5 \cos ^3(c+d x) \sin (c+d x)}{24 a^3 d}+\frac{\cos ^5(c+d x) \sin (c+d x)}{6 a^3 d}+\frac{5 \int \cos ^2(c+d x) \, dx}{8 a^3}\\ &=\frac{5 \cos (c+d x) \sin (c+d x)}{16 a^3 d}+\frac{5 \cos ^3(c+d x) \sin (c+d x)}{24 a^3 d}+\frac{\cos ^5(c+d x) \sin (c+d x)}{6 a^3 d}+\frac{5 \int 1 \, dx}{16 a^3}\\ &=\frac{5 x}{16 a^3}+\frac{5 \cos (c+d x) \sin (c+d x)}{16 a^3 d}+\frac{5 \cos ^3(c+d x) \sin (c+d x)}{24 a^3 d}+\frac{\cos ^5(c+d x) \sin (c+d x)}{6 a^3 d}\\ \end{align*}
Mathematica [A] time = 0.0421645, size = 46, normalized size = 0.58 \[ \frac{45 \sin (2 (c+d x))+9 \sin (4 (c+d x))+\sin (6 (c+d x))+60 c+60 d x}{192 a^3 d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.016, size = 95, normalized size = 1.2 \begin{align*}{\frac{\tan \left ( dx+c \right ) }{6\,d{a}^{3} \left ( \left ( \tan \left ( dx+c \right ) \right ) ^{2}+1 \right ) ^{3}}}+{\frac{5\,\tan \left ( dx+c \right ) }{24\,d{a}^{3} \left ( \left ( \tan \left ( dx+c \right ) \right ) ^{2}+1 \right ) ^{2}}}+{\frac{5\,\tan \left ( dx+c \right ) }{16\,d{a}^{3} \left ( \left ( \tan \left ( dx+c \right ) \right ) ^{2}+1 \right ) }}+{\frac{5\,\arctan \left ( \tan \left ( dx+c \right ) \right ) }{16\,d{a}^{3}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.70905, size = 122, normalized size = 1.54 \begin{align*} \frac{\frac{15 \, \tan \left (d x + c\right )^{5} + 40 \, \tan \left (d x + c\right )^{3} + 33 \, \tan \left (d x + c\right )}{a^{3} \tan \left (d x + c\right )^{6} + 3 \, a^{3} \tan \left (d x + c\right )^{4} + 3 \, a^{3} \tan \left (d x + c\right )^{2} + a^{3}} + \frac{15 \,{\left (d x + c\right )}}{a^{3}}}{48 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.07574, size = 305, normalized size = 3.86 \begin{align*} \frac{15 \, d x \tan \left (d x + c\right )^{6} + 45 \, d x \tan \left (d x + c\right )^{4} + 15 \, \tan \left (d x + c\right )^{5} + 45 \, d x \tan \left (d x + c\right )^{2} + 40 \, \tan \left (d x + c\right )^{3} + 15 \, d x + 33 \, \tan \left (d x + c\right )}{48 \,{\left (a^{3} d \tan \left (d x + c\right )^{6} + 3 \, a^{3} d \tan \left (d x + c\right )^{4} + 3 \, a^{3} d \tan \left (d x + c\right )^{2} + a^{3} d\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 1.80923, size = 454, normalized size = 5.75 \begin{align*} \begin{cases} \frac{15 d x \tan ^{6}{\left (c + d x \right )}}{48 a^{3} d \tan ^{6}{\left (c + d x \right )} + 144 a^{3} d \tan ^{4}{\left (c + d x \right )} + 144 a^{3} d \tan ^{2}{\left (c + d x \right )} + 48 a^{3} d} + \frac{45 d x \tan ^{4}{\left (c + d x \right )}}{48 a^{3} d \tan ^{6}{\left (c + d x \right )} + 144 a^{3} d \tan ^{4}{\left (c + d x \right )} + 144 a^{3} d \tan ^{2}{\left (c + d x \right )} + 48 a^{3} d} + \frac{45 d x \tan ^{2}{\left (c + d x \right )}}{48 a^{3} d \tan ^{6}{\left (c + d x \right )} + 144 a^{3} d \tan ^{4}{\left (c + d x \right )} + 144 a^{3} d \tan ^{2}{\left (c + d x \right )} + 48 a^{3} d} + \frac{15 d x}{48 a^{3} d \tan ^{6}{\left (c + d x \right )} + 144 a^{3} d \tan ^{4}{\left (c + d x \right )} + 144 a^{3} d \tan ^{2}{\left (c + d x \right )} + 48 a^{3} d} + \frac{15 \tan ^{5}{\left (c + d x \right )}}{48 a^{3} d \tan ^{6}{\left (c + d x \right )} + 144 a^{3} d \tan ^{4}{\left (c + d x \right )} + 144 a^{3} d \tan ^{2}{\left (c + d x \right )} + 48 a^{3} d} + \frac{40 \tan ^{3}{\left (c + d x \right )}}{48 a^{3} d \tan ^{6}{\left (c + d x \right )} + 144 a^{3} d \tan ^{4}{\left (c + d x \right )} + 144 a^{3} d \tan ^{2}{\left (c + d x \right )} + 48 a^{3} d} + \frac{33 \tan{\left (c + d x \right )}}{48 a^{3} d \tan ^{6}{\left (c + d x \right )} + 144 a^{3} d \tan ^{4}{\left (c + d x \right )} + 144 a^{3} d \tan ^{2}{\left (c + d x \right )} + 48 a^{3} d} & \text{for}\: d \neq 0 \\\frac{x}{\left (a \tan ^{2}{\left (c \right )} + a\right )^{3}} & \text{otherwise} \end{cases} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.28966, size = 82, normalized size = 1.04 \begin{align*} \frac{\frac{15 \,{\left (d x + c\right )}}{a^{3}} + \frac{15 \, \tan \left (d x + c\right )^{5} + 40 \, \tan \left (d x + c\right )^{3} + 33 \, \tan \left (d x + c\right )}{{\left (\tan \left (d x + c\right )^{2} + 1\right )}^{3} a^{3}}}{48 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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